You could then use Pythagoras to calculate the length of the part of the rafter that's between the ridge and the frame. So the triangle that you're basing your design on is 12 2/3 rise and 25 run. I think you have it nearly right: shouldn't the run be just 25ft, as that's the horizontal distance from the centre to the top of the frame of the house? The height of the ridge is 12 2/3 feet above the top of the frame, and the top of the frame is 25 feet horizontally away from the ridge. Please contact the moderators of this subreddit if you have any questions or concerns. I am a bot, and this action was performed automatically. To help preserve questions and answers, this is an automated copy of the original text. Is that right? I'm not sure if I'm doing this correctly or leaving something out. So the rise would be 12 2/3 so I would convert the mixed number into an improper fraction so that would be 38/3, and then divide the rise 38/3 by the run 26ft, so that would equal 19/39. So the way I understand this is that the pitch of the roof would be the same as the slope. If the ridge is 12 2/3 feet above the top of the frame of the house, what will be the pitch of the roof? Make sure to give the pitch (slope) as a fraction in the simplest form. So, each rafter will have a horizontal length of 26 feet. The roof ridge where two identical rafters will meet will be in the exact middle of the house. The overhang on each side will be 1 foot, so the roof will need to span a total of 52 feet. "Suppose you want to put a gable roof on a section of a house that is 50 feet long. If your post has been solved, please type Solved! or manually set your post flair to solved.
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